long long pairsFormLCM( int n ) {
long long res = 0;
for( int i = 1; i <= n; i++ )
for( int j = i; j <= n; j++ )
if( lcm(i, j) == n ) res++; // lcm means least common multiple
return res;
}
#include <bits/stdc++.h>
#define pii pair <int,int>
#define pll pair <long long,long long>
#define sc scanf
#define pf printf
#define Pi 2*acos(0.0)
#define ms(a,b) memset(a, b, sizeof(a))
#define pb(a) push_back(a)
#define MP make_pair
#define db double
#define ll long long
#define EPS 10E-10
#define ff first
#define ss second
#define sqr(x) (x)*(x)
#define D(x) cout<<#x " = "<<(x)<<endl
#define VI vector <int>
#define DBG pf("Hi\n")
#define MOD 1000000007
#define CIN ios_base::sync_with_stdio(0); cin.tie(0)
#define SZ(a) (int)a.size()
#define sf(a) scanf("%d",&a)
#define sfl(a) scanf("%lld",&a)
#define sff(a,b) scanf("%d %d",&a,&b)
#define sffl(a,b) scanf("%lld %lld",&a,&b)
#define sfff(a,b,c) scanf("%d %d %d",&a,&b,&c)
#define sfffl(a,b,c) scanf("%lld %lld %lld",&a,&b,&c)
#define stlloop(v) for(__typeof(v.begin()) it=v.begin();it!=v.end();it++)
#define loop(i,n) for(int i=0;i<n;i++)
#define REP(i,a,b) for(int i=a;i<b;i++)
#define RREP(i,a,b) for(int i=a;i>=b;i--)
#define TEST_CASE(t) for(int z=1;z<=t;z++)
#define PRINT_CASE printf("Case %d: ",z)
#define CASE_PRINT cout<<"Case "<<z<<": "
#define all(a) a.begin(),a.end()
#define intlim 2147483648
#define infinity (1<<28)
#define ull unsigned long long
#define gcd(a, b) __gcd(a, b)
#define lcm(a, b) ((a)*((b)/gcd(a,b)))
using namespace std;
#define maxx 10000007
bitset<maxx/2>vis;
vector<int>prime;
void sieve()
{
int x=maxx/2, y=sqrt(maxx)/2;
for(int i=1;i<=y;i++)
{
if(vis[i]==0)
{
for(int j=(i*(i+1)*2);j<x;j+=(2*i)+1)
vis[j]=1;
}
}
prime.pb(2);
for(int i=3;i<maxx;i+=2)
if(vis[i/2]==0)
prime.pb(i);
}
int main()
{
sieve();
int t;
sf(t);
TEST_CASE(t)
{
ll n;
sfl(n);
ll ans=1;
ll root=sqrt(n);
for(int i=0; i<SZ(prime) && prime[i]<=root;i++)
{
if(n%prime[i]==0)
{
int cnt=0;
while(n%prime[i]==0)
{
n/=prime[i];
cnt++;
}
ans*=(2*cnt+1);
root=sqrt(n);
}
}
if(n>1)
{
ans*=3;
}
PRINT_CASE;
printf("%lld\n",(ans/2)+1);
}
return 0;
}
কোন মন্তব্য নেই:
একটি মন্তব্য পোস্ট করুন